【C1】题选项是() 材料
What enables some people to get big creative breakthroughs while others only get small and non-creative breakdowns, blaming themselves and society? Are some people "gifted"? Are there other factors 【C1】work—factors that we have more control over than we think?
While nobody can deny the 【C2】that some people seem to be blessed with particular creativity, research shows that anyone can 【C3】 their chances of coming up with new and original ideas 【C4】they would only engage themselves more in the process of 【C5】. It’s the old Thomas Edison thing about "discovery 【C6】99 percent perspiration (汗水) and I percent inspiration." 【C7】______, the studies prove this: great creative breakthroughs usually happen only 【C8】intense periods of struggle. It is sustained effort towards a specific goal 【C9】eventually prepares for great creative insights.
This kind of sustained effort does not always 【C10】immediate results, a fact that not only separates the innovators (革新者) from non-innovators, but 【C11】leads some people to conclude that it is just not 【C12】for them. "Maybe I should have gone to medical school like my mother wanted," they wonder when the breakthrough is 【C13】to be found. Alas, one forgets during their inevitable encounters 【C14】______ self-doubt, that the big surprise is never 【C15】. Indeed, it can happen at any time and place.ly separates the innovators (革新者) from non-innovators, but 【C11】leads some people to conclude that it is just not 【C12】 for them. "Maybe I should have gone to medical school like my mother wanted," they wonder when the breakthrough is 【C13】to be found. Alas, one forgets during their inevitable encounters 【C14】 self-doubt, that the big surprise is never 【C15】. Indeed, it can happen at any time and place.
单选题

【C1】题选项是()

A. to
B. in
C. at
D. by

查看答案
该试题由用户946****42提供 查看答案人数:48250 如遇到问题请 联系客服
正确答案
该试题由用户946****42提供 查看答案人数:48251 如遇到问题请联系客服

相关试题

换一换
单选题
【C1】题选项是()
A.to B.in C.at D.by
答案
单选题
测量了一个七圈板对接式弧形顶卧式金属罐各圈板外周长C1=8004㎜;C1=8003㎜;C1=8012㎜;C1=8007㎜;C1=8008㎜;C1=8009㎜;C1=8005㎜,中部圆筒平均周长是()。
A.8006.9㎜ B.8006.8㎜ C.8006.7㎜ D.8006.6㎜
答案
主观题
下列程序的运行结果是 (已知字母A的ASCII码值为65) main() { char c1=’B’; int x=10; c1=c1+x; printf(“%c,%d ”,c1,c1); }
答案
主观题
以下程序运行后输出的结果是______。 void main() char c1,c2; for (c1=’0’,c2=’9’;c1<c2;c1++,c2--) printf("%c%c",c1,c2); printf("");
答案
主观题
程序段char c1[19]="This is a "; char c2[]="string."; strcat(c1,&c2[2]);puts(c1);输出结果是
答案
主观题
有以下程序: include <stdio.h> main() char c1,c2; scanf("%c",&c1); while(c1<6511c1>90) scanf("% c",&c1); c2=c1+32; printf("%c,%c",c1,c2); 程序运行输入65<回车>后,能否输出结果、结束运行(请回答能或不能)______。
答案
多选题
以下程序段运行的输出结果是()#includeint main(){ char c1,c2; c1=’C’-2; c2=97; printf(“%d,%c”,c1,c2); return 0;}
A.A,97 B.65,a C.A,a D.65,97
答案
主观题
若有说明 char c1[ ] = "good"; 则函数strlen(c1)的返回值是
答案
单选题
C1()
A.补体经典激活途径的固有成分 B.补体旁路激活途径的固有成分 C.补体三条激活途径的共同成分 D.补体旁路途径激活物 E.补体经典途径激活物
答案
单选题
有以下程序 #include main() { char c1=’1’,c2=’2’; c1=getchar(); c2=getchar(); putchar(c1); putchar(c2); } 当运行时输入:a后,以下叙述正确的是()
A.变量 B.C1被赋予字符a,c2被赋予回车符 C.程序将等待用户输入第2个字符 D.变量c1被赋予字符a,c2中仍是原有字符2 E.变量c1被赋予字符a,c2中将无确定值
答案
热门试题
判断加减法溢出时,可采用判断进位的方式,如果符号位的进位是C0­,最高位的进位C1, 产生溢出的条件是:①C0产生进位②C1产生进位③C0和C1都产生进位④C0和C1都不产生进位⑤C0产生进位,C1不产生进位⑥C0不产生进位,C1产生进位() C1、C4、C2是() 有以下程序段: char c1=’1′,c2=’2′;c1=getchar(); c2=getchar();putchar(c1); putchar(c2);运行时从键盘上输入:a↙ 后,以下叙述中正确的是() 以下程序运行时若输入:a ,则叙述正确的是()。#includeint main(){ char c1=’1′,c2=’2′; c1=getchar(); c2=getchar(); putchar(c1); putchar(c2); return 0;} 下列程序的输出结果是()。 main(){char c1=97,c2=98; printf(“%d %c”,c1,c2); } 下列程序的输出结果是().main(){char c1=97,c2=98;printf("%d %c",c1,c2);} 在交流电路中,电容C1和C2并联,其C1为C2的3倍,则通过C1的电流是C2的倍() 现有1个char类型的变量c1=66和1个整型变量i=2,当执行c1=c1+(char)i;语句后,c1的值为() 中国大学MOOC: 设 char c1=’A’,执行语句printf(“%%”,c1);的输出结果是()。 Dukes C1() Dukes C1() 有以下程序#includeint main(){ char c1=’1′,c2=’2′;c1=getchar();c2=getchar();putchar(c1);putchar(c2);return 0;}当运行时输入:a 后,以下叙述正确的是() 以下程序段运行的输出结果是()#includeint main(){ char c1=97; int c2=1; printf(“%d,%c”,c1,c1+c2); return 0;} 给定:char c1=97,c2=98;printf(“%d %c”,c1,c2),输出结果是?(字符’a’的ASCII码为97)() 若有以下段,int c1=1,c2=2,c3;c3=1.0/c2*c1;则执行后,c3中的值是 有以下程序#include main(){ char c1,c2; c1=’A’+’8′-‘4′; c2=’A’+’8’-‘5’; printf(“%c,%d”,c1,c2);}已知字母A的ASCII码为65,程序运行后的输出结果是 C1、C4、C2() 符号C1表示() C1类缺陷的分值是() 如果一个类C1通过继承已有类C而创建,则将C1称作()。
购买搜题卡 会员须知 | 联系客服
会员须知 | 联系客服
关注公众号,回复验证码
享30次免费查看答案
微信扫码关注 立即领取
恭喜获得奖励,快去免费查看答案吧~
去查看答案
全站题库适用,可用于E考试网网站及系列App

    只用于搜题看答案,不支持试卷、题库练习 ,下载APP还可体验拍照搜题和语音搜索

    支付方式

     

     

     
    首次登录享
    免费查看答案20
    微信扫码登录 账号登录 短信登录
    使用微信扫一扫登录
    登录成功
    首次登录已为您完成账号注册,
    可在【个人中心】修改密码或在登录时选择忘记密码
    账号登录默认密码:手机号后六位